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![Amy Shah](https://secure.gravatar.com/avatar/c7c021461c8b1f8a1b3c6cafcb0e95bd?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Amy Shah
25,337 PointsWhat am I missing here - Razor list question
I have done the exercise just like the example in the video but I dont see what it is not passing. It said I did not close out my <li> element but I did. Not sure what to do at this point
@{
Layout = null;
var title = "Super Mario 64";
var description = "Super Mario 64 is a 1996 platform video game developed and published by Nintendo for the Nintendo 64.";
var characters = new string[]
{
"Mario",
"Princess Peach",
"Bowser",
"Toad",
"Yoshi"
};
}
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width" />
<title>Video Game Detail</title>
</head>
<body>
<div>
<h1>@title</h1>
<h5>Description:</h5>
<div>@description</div>
<h5>Characters:</h5>
<div>
<ul>
@foreach (var character in characters)
{
<li>@characters</li>
}
</ul>
</div>
</div>
</body>
</html>
1 Answer
![Steven Parker](https://uploads.teamtreehouse.com/production/profile-photos/969492/micro_tool_chess_set_2.jpg)
Steven Parker
230,688 PointsYou're trying to print the collection instead of the individual strings.
You created a character variable in your loop, but in each list item you have @characters (plural), which represents the entire collection.