Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Letter Game App Even or Odd Loop

Ayodeji Olukoya
Ayodeji Olukoya
1,475 Points
Posted by Ayodeji Olukoya
Ayodeji Olukoya
1,475 Points

what do you mean by putting the number in the hole?

what do you mean by putting the number in the hole?

even.py 
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while true:
    get_num=random.randint(1,99)
    if get_num % 2 = 0:
        print("{} is even" .format(get_num)

1 Answer

Andreas cormack
.a{fill-rule:evenodd;}techdegree seal-36
Andreas cormack
Python Web Development Techdegree Graduate 33,011 Points

Hi Ayodeji

Use the even_odd function to work out if the number is even or odd. 

while start:
    get_num = random.randint(1,99)
    if even_odd(get_num):
        print("{} is even".format(get_num))
    else:
        print("{} is odd".format(get_num))
    start-=1