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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by cb123
cb123
Courses Plus Student 9,858 Points

What is optimal way of solving disemvowel?

I did complete the disemvowel challenge by using loop (v in vowels) within a loop of (w in word) to iterate, then reconstructed a new word (new_word += w) from characters where w == v did not occur.

Is there a more efficient way?

1 Answer

Manish Giri
Manish Giri
16,266 Points
Manish Giri
Manish Giri
16,266 Points

You could use List Comprehension and the .join() function to first create a list that does not have the vowels, then use .join() to create a string from the list -

def disemvowel(word):
    vowels = ["a", "e", "i", "o", "u"]
    return "".join(w for w in word if w.lower() not in vowels)

If I break it down -

  1. w for w in word basically gives you all the letters in word, because word being a str object is iterable.
  2. the condition if w.lower() not in vowels is a containment check - it checks if the current letter is not a vowel, and if it isn't, it is returned in the list.
  3. The final list is joined to form a string using .join().
cb123
cb123
Courses Plus Student 9,858 Points

very nice. I did not realize that you could write python in this way. Hopefully this approach will be presented in future instructions. Thanks.