Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Game Development How to Make a Video Game Pickups Spawn Pickups Randomly

Posted by Derek Markman
Derek Markman
16,291 Points

What is the access modifier set to by default for variables declared and initialized inside of a method?

If we declare a variable inside of a method:

void update() {
//does positionX get set to public by default?
float postionX = Random.Range(-spawnArea, spawnArea);
}

2 Answers

Seth Kroger
Seth Kroger
56,414 Points
Seth Kroger
Seth Kroger
56,414 Points

Variables inside are method are local to that method only and can't be accessed outside it. This includes method parameters as well. Additionally if you declare variables inside a code block surrounded by curly braces inside the method, they are only accessible inside those braces, not outside. They don't have access modifiers because access modifiers only make sense with class fields or methods.

Derek Markman
Derek Markman
16,291 Points
Derek Markman
Derek Markman
16,291 Points

Thanks Seth Kroger I understand now.