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Python Python Collections (2016, retired 2019) Dictionaries Teacher Stats

Posted by newpal
newpal
1,717 Points

what is wrong with my code?

def courses(dict): available_courses = [] for value in dict.values(): available_courses.append(", ".join(value)) return available_courses

teachers.py 
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict):
    count = 0
    for key in dict.keys():
        count += 1
    return count

def num_courses(dict):
    count = 0
    for value in dict.values():
        count += len(value)
    return count

def courses(dict):
    available_courses = []
    for value in dict.values():
        available_courses.append(", ".join(value))
    return available_courses
newpal
newpal
1,717 Points

Could you please provide the answer to this code challenge?

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

The courses returned should be individual items, but this code will return strings of comma-separated course names.

newpal
newpal
1,717 Points

Thank you Steven. Any ideas on how to make my code return individual items?

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You won't need to "join" anything. The entire purpose of that function is to convert individual items into a string.

newpal
newpal
1,717 Points

But if I do not use "join", my code returns list inside a list.

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

It does that if you use "append". But there's another method that combines lists differently.

newpal
newpal
1,717 Points

Yes! it is the .extend() method! :) Thank you Steven!