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Start your free trialOdane Williams
6,692 PointsWhy am I getting an unexpected keyword argument exception if it is defined after the function?
I can't see where my syntax is wrong
def favorite_food(dict):
return "Hi, I'm {name} and I love to eat {food}!".format(name, food)
favorite_food(name= "Bob", food= "pizza")
1 Answer
Steven Parker
231,269 PointsYour function call isn't passing a dictionary. A dictionary would be enclosed in braces, and the keys would be separated from the values with colons instead of equal signs.
But the challenge doesn't require you to call the function at all, only define it. And inside the definition, the terms "name" and "food" are referenced but not defined.
You won't need them there either if you use the unpacking ("splat") operator on the dictionary that is passed in as the function argument.