Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialJanneke Polderman
7,157 PointsWhy did my .toggle stop working after I added the changeColor function?
After I added the changeColor function I cannot use the New Color button anymore. Why? Is there something wrong with the code?
//When new color is pressed $("#revealColorSelect").click(function(){ //Show color select or hide the colorselect changeColor(); $( "#colorSelect").toggle(); });
//update the new color span function changeColor() { var r = $ ("#red").val(); var r = $ ("#green").val(); var r = $ ("#blue").val(); $("#newColor").css("background-color", "rgb(" + r + "," + g + ", " + b + " )"); }
Later on I saw that Toggle is predecated. What else can you use instead of this?
2 Answers
Henrik Christensen
Python Web Development Techdegree Student 38,322 PointsAll your variables are named var r but they should be different
//update the new color span
function changeColor() {
var r = $ ("#red").val();
var r = $ ("#green").val(); // should be var g
var r = $ ("#blue").val(); // should be var b
$("#newColor").css("background-color", "rgb(" + r + "," + g + ", " + b + " )");
}
Asia Chan
11,007 PointsYour variables are the same "r"
Changed this:
//update the new color span function
changeColor() {
var r = $ ("#red").val();
var r = $ ("#green").val();
var r = $ ("#blue").val();
$("#newColor").css("background-color", "rgb(" + r + "," + g + ", " + b + " )"); }
to this:
//update the new color span function
changeColor() {
var r = $ ("#red").val();
var g = $ ("#green").val();
var b = $ ("#blue").val();
$("#newColor").css("background-color", "rgb(" + r + "," + g + ", " + b + " )"); }