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Emilio Andere
495 PointsWhy is this incorrect
check please
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
messy_list.pop(3)
messy_list.insert(0, 1)
messy_list.pop(1)
messy_list.remove([1, 2, 3])
messy_list.pop(4)
# Your code goes below here
1 Answer
Teal Larsen
21,066 PointsWhen you begin your list contains 6 things that have the indices 0-5. You then remove 1 and insert 1, so you still have 6 things. Then you remove 2 items (using the pop and remove methods) which leaves 4 items in your list, they have the indices 0, 1, 2, and 3. So when you call the messy_list.pop(4) you are trying to remove the item at index 4 but you don't have an index 4. Because the index starts at 0, your 4th and final item in the current list has an index of 3. To remove the last item you should use messy_list.pop(3) or just messy_list.pop as that will remove the last item by default.
Emilio Andere
495 PointsEmilio Andere
495 PointsTeal you're very helpful, THANK YOUU