Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Collections and Control Flow Control Flow With Conditional Statements FizzBuzz Challenge

Jabor Al thani
Jabor Al thani
2,926 Points
Posted by Jabor Al thani
Jabor Al thani
2,926 Points

Why isn't the function going through ?

Ive replaced print with return and then thing still doesn't go through ?

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
for n in 1...100 {
    if ( n % 3 == 0 ) && ( n % 5 == 0 ) {
        return("FizzBuzz")
    } else if ( n % 3 == 0 ) {
         return("Fizz")
    } else if ( n % 5 == 0 ) {
         return("Buzz")
    } else {

  return "\(n)"
}
}

2 Answers

Brandon Mahoney
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Brandon Mahoney
iOS Development with Swift Techdegree Graduate 30,149 Points
Brandon Mahoney
.a{fill-rule:evenodd;}techdegree seal-36
Brandon Mahoney
iOS Development with Swift Techdegree Graduate 30,149 Points

You don't need the for loop, you are just checking for n. Also the last else is unnecessary as well.

func fizzBuzz(n: Int) -> String {
    if ( n % 3 == 0 ) && ( n % 5 == 0 ) {
        return("FizzBuzz")
    } else if ( n % 3 == 0 ) {
         return("Fizz")
    } else if ( n % 5 == 0 ) {
         return("Buzz")
    } 

  return "\(n)"
}
Jabor Al thani
Jabor Al thani
2,926 Points
Jabor Al thani
Jabor Al thani
2,926 Points

Thanks for the help Brandon , it finally went through .