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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by felix kjelberg
felix kjelberg
890 Points

why its giving error wrong number while its working perfectly in pycharm

.

even.py 
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2


start = 5

while start == 5:
    rand = random.randint(1, 99)
    num = even_odd(rand)
    if num is True:
        print('{} is even'.format(rand))
    else:
        print("{} is odd".format(rand))

    start -= 1

1 Answer

behar
behar
10,799 Points

Hey felix! Your super close! The only issue with your code is that your saying the while loop should run only when start is equal to 5? But it should run untill start is equal to 0. So instead of saying:

while start == 5:

say:

while start: #This will run untill start is falsey or 0 if you like.
felix kjelberg
felix kjelberg
890 Points

Thanks bro it worked