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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Alex Salas
Alex Salas
3,429 Points

word_count()

What am I missing here? It works on my PC.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(rec):
    rec_list = rec.lower().split(" ")
    dict = {}
    for word in rec_list:
        if word in dict:
            dict[word] += 1
        else:
            dict[word] = 1
    return dict

print(word_count("I do not like it Sam I Am"))

3 Answers

reanimator313
reanimator313
6,005 Points

the problem is with .split(" " ), just use .split() to split all whitespace ('Tab', 'Space',...)

Alex Salas
Alex Salas
3,429 Points

That was it. Not sure why it didnt work. It works in my computer. Thank you much !

Eugen Klimenko
Eugen Klimenko
7,622 Points
Eugen Klimenko
Eugen Klimenko
7,622 Points

What is an issue? It looks like everything okay.

The function is fine. Now you have to call it: word_count("I do not like it Sam I Am")

Alex Salas
Alex Salas
3,429 Points

Good catch Eugen. I called it and this is what I get:

Bummer! Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!

Eugen Klimenko
Eugen Klimenko
7,622 Points
Eugen Klimenko
Eugen Klimenko
7,622 Points

Hmm.. It looks strange. Can you try this?

print(word_count("I do not like it Sam I Am"))
Alex Salas
Alex Salas
3,429 Points

No luck. I have updated the code above so you can see what I have. Error: Bummer! Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!