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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Mimon Copitman
Mimon Copitman
1,242 Points
Posted by Mimon Copitman
Mimon Copitman
1,242 Points

word_count challenge i don't understand that!!! - my code is right

i'm not getting it!, what i'm missing here, when i run it on workplace it giving me the right answer

wordcount.py 
def word_count(string):
    string_list = string.lower().split(" ")
    string_dict = {}

    for word in string_list:
        if word in string_dict:
            string_dict[word] += 1
            continue
        else:
            string_dict[word] = 1
    return string_dict

word_count("I do not like it Sam I Am")

1 Answer

Christopher Shaw
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PLUS
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Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points
Christopher Shaw
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points

This is a common stumbling block in this challenge. Try this line and it produces unexpected results due to the extra spaces:

word_count("I do   not  like it Sam  I    Am")

Hint: It is in the way you used split().