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Richard Jones
3,500 PointsWorking with Arrays: code challenge
I am having difficulty with the third part of the code challenge. We were taught how to remove values from arrays but it was never discussed in the video how to add that value to a constant. Amazing how many times the code challenges ask me to do something not explained. You guys must be having quite a laugh.
So the only way I can move on with my lesson is to post this question, find my question in the community and follow the link to the discussion about my lesson and see if someone can explain what to do. How nice would it be to add a link on the code challenge page directly to the discussion about that lesson. I guess it is better to stump your students.
// Enter your code below
var arrayOfInts = [1,2,3,4,5,6]
arrayOfInts.append(12)
arrayOfInts = arrayOfInts + [13]
let value = arrayOfInts[4]
1 Answer
Moritz Lang
25,909 PointsHi Richard,
removeAtIndex(0)
returns the value you're removing.
The correct answer would be as easy as this:
var arrayOfInts = [1, 2, 3, 4, 5, 6]
arrayOfInts.append(7)
arrayOfInts += [8]
let value = arrayOfInts[4]
let discardedValue = arrayOfInts.removeAtIndex(5)
Alex Key
463 PointsAlex Key
463 PointsUpdated for swift 3: you'll need to use the new syntax for .removeAtIndex(5) which is now:
remove(at: 5)