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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Shazlyne Vambe
Shazlyne Vambe
3,942 Points

wrong number of prints.

what have i left out or what am i doing wrong?

even.py 
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while (start):
    num = random.randint(1, 99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
        start -=1
Shazlyne Vambe
Shazlyne Vambe
3,942 Points

tried doing it this way still got wrong number of prints:

import random start = 5 def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2

while start: random_num = random.randint(1, 99) if even_odd(random_num) == True: print("{} is even".format(random_num)) else: print("{} is odd".format(random_num)) start -=1

1 Answer

behar
behar
10,799 Points
behar
behar
10,799 Points

Hey Shazlyne! Your only subtracting 1 from start if the number is odd, do it for both odd and even.