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DJ Segler
182 PointsChallenge Issue
Working on Obj-C and running into an issue with one of the challenges. Unfortunately, it doesn't provide any hints as to what it's looking for and what I've typed seems correct from what I can tell. Sure would be nice to get a more descriptive response than "bummer".
Here's a link to the challenge: http://teamtreehouse.com/library/arrays-4
And here's what I've typed which seems to match the instructions. Either the instructions are wrong or I'm missing something fundamental...
#include <stdio.h>
int main()
{
char alpha = 'a';
char bravo = 'b';
}
6 Answers
eirikvaa
18,015 PointsI think the only thing you have to write is this:
char alpha = 'a';
char bravo = 'b';
That is, leave out the main function.
DJ Segler
182 PointsI have done it that way as well. It still doesn't like it.
DJ Segler
182 PointsWell - now it does.
Did it about 10 times like that on my ipad last night and it never worked so I started adding the other structure components.
If it has only given me a hint like, "You only need to create the variable declarations." Or, "Remember that character declarations should use single quotes instead of double quotes." Etc...
Anything would have been better than "Bummer".
DJ Segler
182 PointsAnd so here it goes again... On the last task of that challenge, it's asked me to print out the results. Here's what I've typed:
char alpha = 'a';
char bravo = 'b';
char letters[2] = {alpha, bravo};
printf ("Result is %c \n", letters);
And it doesn't like it, giving me a hint of: "Bummer! The correct format character for a 'char' is '%c'." Clearly, I'm already using '%c'.
Am I missing something?
eirikvaa
18,015 PointsIn part 3 it asked you to assign the variable bravo the the second element in the letters array. I passed with the below solution:
char alpha = 'a';
char bravo = 'b';
char letters[2] = {alpha, bravo};
bravo = letters[1];
printf("letters %c %c", letters[0], letters[1]);
Matthew Mascioni
20,444 PointsNice one, Eirik Vale Aase ! Never considered that one.
Matthew Mascioni
20,444 PointsI just ran through the code challenge. The following code seems to have worked:
printf("letters %c %c", alpha, bravo);
You have the correct format specifier, however, in the instructions, it says your output should look like 'letters a b'. We defined chars 'alpha' and 'bravo' to have the values 'a' and 'b' respectively, already. All we have to do is print them out using the %c format specifier twice, and listing alpha and bravo variables as the second and third arguments for the printf() function.
DJ Segler
182 PointsUnderstood. I come from an Actionscript 3 background where I can just add an array itself to the string I'm appending to and it just lists it out... Didn't realize that I have to explicitly list each element.
Thanks for the help and I apologize if my tone is a bit harsh today. A little frustrated that simple things are going so slow. Not enough hints or references to go with the challenges make it more frustrating. Glad you guys are quick to respond here.
Thanks again!
eirikvaa
18,015 PointsNo worries. I too come from ActionScript 3 since that was taught in computer class at my school. Never liked AS3, though - always hated Flash.