Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Foundations Functions Return Values

This is driving me crazy. What am i missing?

<script>
      function arrayCounter (a){
        if (typeof a === 'undefined', 'string', 'number'){
                return 0;}
            return a.length;
      }
</script>

I need to return the length of a, if a is an array.. Help

without the 'if' statement, this function returns the length of the array..

I don't know why it's catching 'a' though.. maybe this might help

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/typeof

Thanks i got it finally, looking on the internet, the answer is:

function arrayCounter(array) { if (typeof array === "string" || typeof array === "number"|| typeof array === "undefined") { return 0; } else { return array.length; } }

1 Answer

After checking out MDN (thanks, Thomas), I think this should work:

function arrayCounter( a ) {
    if ( Array.isArray( a ) ) {
        return a.length;
    }

    return 0;
}

My bad, didn't realize this had already been answered.