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iOS

Posted by Gregg Mojica
Gregg Mojica
11,506 Points

UiImage Code Challenge

Hi Guys, Stuck on this question:

Link http://teamtreehouse.com/library/ios-development/build-a-selfdestructing-message-iphone-app/further-enhancing-the-user-interface-and-experience/customizing-table-view-cell-disclosure-indicators-2

Question Next we need a UIImageView to display the pizza slice UIImage. Create a UIImageView variable and set its 'image' property to the UIImage variable you just created.

My Code [UIImage imageNamed: @"pizza_slice"]; UIImageView *myView = [[UIImageView alloc] init];

Not sure where to go from here...

Thanks!

4 Answers

Stephen Whitfield
Stephen Whitfield
16,771 Points
Stephen Whitfield
Stephen Whitfield
16,771 Points

or you could stick it all on one line. like this:

            UIImageView *myImage = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"pizza_slice"]];
Gregg Mojica
Gregg Mojica
11,506 Points
Gregg Mojica
Gregg Mojica
11,506 Points

Figured it out! UIImage *images; [UIImage imageNamed: @"pizza_slice"]; UIImageView *myView = [[UIImageView alloc] init]; myView.image = images;

R Brewster
R Brewster
15,328 Points
R Brewster
R Brewster
15,328 Points

This seems to work

[UIImage imageNamed:@"pizza_slice"]; UIImageView *pizzaImage = [[UIImageView alloc] init]; pizzaImage.image = [UIImage imageNamed:@"pizza_slice"];

Stephen Whitfield
Stephen Whitfield
16,771 Points

It works, but you're breaking the DRY (Don't Repeat Yourself) principle. The UIImage declaration in that first line is not needed, as you have already assigned that image to your UIImageView in the last line. Take that out and you'll be fine.

R Brewster
R Brewster
15,328 Points
R Brewster
R Brewster
15,328 Points

Good point. Thanks Stephen.