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Python Introducing Lists Build an Application Add Items

Posted by ja5on
ja5on
10,338 Points

DONE is the result

https://w.trhou.se/6hhguqz2nq

My Input.
eggs
ham
cheese

My result.
DONE
Added! List has items.

f string not working but i know why.
I would like to see a list but why am i getting done as the result?

2 Answers

Asher Orr
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Asher Orr
Python Development Techdegree Graduate 9,409 Points
Asher Orr
.a{fill-rule:evenodd;}techdegree seal-36
Asher Orr
Python Development Techdegree Graduate 9,409 Points

Hi Jas0n!

Here's the problem: you're calling the add_to_list function only if "DONE" is the user's input.

To see what I mean, check out the comments:

show_help()
#display message

while True:
    new_item = input("> ")
    # ask for user input

    if new_item == "DONE":
    # if the input is "DONE," break out of the loop.
    # then call the add_to_list function.
        break
    elif new_item == "HELP":
    # if the input is "HELP," display the show_help message and continue the loop.
        show_help()
        continue

add_to_list(new_item)
#when your while loop breaks, call this function.

The add_to_list function is called when the loop breaks. The loop breaks only when new_item == "DONE".

To fix the problem, adjust your code to to call that function if something other than "DONE" is entered.

I hope this helps. Let me know if you have further questions!

ja5on
ja5on
10,338 Points

Or could i call the list when done is entered, does that make sense? while True: new_item = input("> ")

if new_item == "DONE":
    break
elif new_item == "END":
    print(add_to_list(new_item))
elif new_item == "HELP":
    show_help()
    continue

I did the above but still no luck Think im lost

I'm tying to print the list upon DONE I think this program is above my knowledge

Asher Orr
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Asher Orr
Python Development Techdegree Graduate 9,409 Points
Asher Orr
.a{fill-rule:evenodd;}techdegree seal-36
Asher Orr
Python Development Techdegree Graduate 9,409 Points

You could call the list when "DONE" is entered. In the new code, you're printing the add_to_list function if the user's input is "END".

Compare it to this code:

while True:
    new_item = input("> ")
    #ask for user's input
    if new_item == "DONE":
        break
    #if input is "DONE", break out of the loop.
    elif new_item == "HELP":
        show_help()
        continue
    #but if the input is "HELP", call show_help function and repeat the loop.
    else:
        add_to_list(new_item)
    #if input isn't DONE or HELP, call the add_to_list function!

To display all the contents in the list, you could create a show_list function and add it to your script.

Does this make sense?

ja5on
ja5on
10,338 Points
ja5on
ja5on
10,338 Points

shopping_list = []

def add_to_list(item):
shopping_list.append(item)
print("Added! List has items.".format(len(shopping_list)))

def show_help():
print("What should we pick up at the store?")
print("""
Enter 'DONE' to stop adding items.
Enter 'HELP' for this help.
""")

show_help()

while True:
new_item = input("> ")
### ### ### ### Below i added a new function to show the list is this what you mean.
if new_item == "DONE":
def show_list():
print(shopping_list)
show_list()
break 

elif new_item == "HELP":                                                                                                                       
       show_help()                                                                                                                                             
       continue                                                                                                                                            

else:
       add_to_list(new_item)