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Start your free trialThomas Greer
1,472 PointsHow do I get different error codes based on different user input?
What am I missing here?
TICKET_PRICE = 10
tickets_remaining = 100
while tickets_remaining >= 1: print("There are only {} tickets remaining. Buy them fast!".format(tickets_remaining)) name = input("What is your name? ")
number_of_tickets = input("Hey {}, how many tickets would you like to buy? ".format(name))
try:
number_of_tickets = int(number_of_tickets)
if number_of_tickets > tickets_remaining:
raise ValueError("There are only {} tickets remaining".format(tickets_remaining))
except ValueError as err:
print("Uh oh! We ran into an issue. {}. Please try again".format(err))
else:
total_due = number_of_tickets * TICKET_PRICE
confirm = input("{}, your total will be {} for {} tickets. Would you like to proceed? Y/N ".format(name, total_due, number_of_tickets))
if confirm.lower() == "y":
# TODO: Gasther credit card information and process it.
print("SOLD! Thank you for your purchase!")
tickets_remaining -= number_of_tickets
else:
print("Thanks anyway, {}!".format(name))
print("There are no more tickets remaining. Sorry!")
Everything runs as it should except when the user types in a non numerical value they get the error: "Uh oh! "We ran into an issue. invalid literal for int() with base 10: 'blue'. Please try again "
1 Answer
Steven Parker
231,172 PointsThe message is also "running as it should". Performing the "int" function on the input raises a ValueError when the input contains something other than a number. Then the print formatting includes the system error text into the message. The system text correctly (if perhaps a bit over-technically) identifies the reason for the error.
You might want to look at some of the other questions asked about this video (under the "Questions" tab near the bottom of the page). Several of the answers contain suggestions for alternative ways to respond to the error.