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Start your free trialShannon Ferguson
1,221 PointsI am hung up on this question.
Here is a multi-dimensional list of musical groups. The first dimension is group, the second is group members.
Can you
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"]
]
for item in musical_groups:
print(", ".join(musical_groups[item]))
3 Answers
Travis Alstrand
Treehouse Project ReviewerHey there Shannon Ferguson !
Since we are already looping through each 'item' inside of musical_groups
, we don't need to specify it's placement within that list.
Just telling it to print the current 'item' it's looping across should do the trick
for item in musical_groups:
print(", ".join(item))
Asher Orr
Python Development Techdegree Graduate 9,409 PointsHi Shannon! This is the syntax for the .join method:
string.join(iterable)
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"],
]
for item in musical_groups:
print(", ".join(musical_groups[item]))
In your current code, you're iterating through each item. That's your iterable- if you replace what's in the parentheses after join with item (your iterable), it should pass the challenge.
I hope this helps. Let me know if you have any questions!
Nicole Groenewald
1,031 PointsWhen I do this code I get "Traceback (most recent call last): File"/home/treehouse/workspace/music.py", line 12 in <module> print(", ".joinmusical_groups[groups])) TypeError: list indices must be integers or slices, not list
Here's all my code, just in case
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"],
]
# Your code here
for groups in musical_groups:
print(", ".join(musical_groups[groups]))
Asher Orr
Python Development Techdegree Graduate 9,409 PointsWhen you enter this code:
for groups in musical_groups:
You are looping through each list within musical_groups. "groups" essentially means "each list within musical_groups."
Each list within musical_groups has several strings (the members of the band/group.) To pass the challenge, you need to join the strings together.
Remember, this is the syntax for the .join() method:
string.join(iterable)
for groups in musical_groups:
string.join(iterable)
"groups" is your iterable.
print(", ".join(musical_groups[groups]))
A list index can't be another list- that type of syntax doesn't work in Python. That's why you're getting the TypeError.
Does this answer your question?
Nicole Groenewald
1,031 Pointsyes, thanks!