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JavaScript JavaScript Loops Working with 'for' Loops The Refactor Challenge – Duplicate Code

Posted by Jessaly Sinchico
Jessaly Sinchico
1,485 Points

I checked my work, but I'm still not able to see the random colors. I see the numbers but the color is the problem.

let html = '';

const randomValue = () => Math.floor(Math.random() * 256);

function randomRGB(value) {

const color = rgb( ${value()}, ${value()}; ${value()} );

return color;

}

for ( let i = 1; i <= 10; i++ ) {

html += <div style="background-color: ${randomRGB(randomValue)}">${i}</div>;

}

document.querySelector('main').innerHTML = html;

2 Answers

jb30
jb30
44,806 Points

Try changing const color = rgb( ${value()}, ${value()}; ${value()} ); to const color = rgb( ${value()}, ${value()}, ${value()} ); with a , to separate the second and third values instead of ;

Jessaly Sinchico
Jessaly Sinchico
1,485 Points
Jessaly Sinchico
Jessaly Sinchico
1,485 Points

Thank you so much! I was able to fix the error and it worked!