Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Introducing Lists Build an Application Multidimensional Musical Groups

Posted by Robson Possidonio
Robson Possidonio
977 Points

one way to answer?

I think I've figured out another way to solve this task, but I keep getting an error. are alternative answers a no no?

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
# Your code here

def test(params):
    for param in params:
        print(*param, sep = ", ")


test(musical_groups)

2 Answers

Steven Parker
Steven Parker
229,952 Points
Steven Parker
Steven Parker
229,952 Points

Some challenges are as much about practicing a specific method as they are about producing the expected output. The instructions in this case asked you to "output the members joined together with a ", " comma space as a separator".

Your approach would produce the same output but it doesn't join the members together (using the "join" string method).

Robson Possidonio
Robson Possidonio
977 Points
Robson Possidonio
Robson Possidonio
977 Points

understood. thanks!