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iOS Functions in Swift Adding Power to Functions Function Parameters

ahmed abdelnaser
ahmed abdelnaser
5,261 Points
Posted by ahmed abdelnaser
ahmed abdelnaser
5,261 Points

what

what?

functions.swift 
// Enter your code below
func getRemainder(value a: Int, divisor b: Int) -> (Int) {
  var remainder = a % b
  return remainder
}
let result = getRemainder(value: 10, divisor: 3)
Shay Paustovsky
Shay Paustovsky
285 Points

Remove the parenthesis from the (Int) after the arrow and everything should work fine

1 Answer

Clark Reilly
Clark Reilly
6,204 Points
Clark Reilly
Clark Reilly
6,204 Points

Should be: getRemainder(...) -> Int not -> (Int)

Also, remainder should be a constant and, if you really want to save space, you can directly return a%b without assigning it to a variable (these steps aren't nesseccary and not fixing them won't prevent your code from compiling. They just save space)