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Python Flask Basics Welcome to Flask Request args

Dillon Reyna
Dillon Reyna
9,531 Points
Posted by Dillon Reyna
Dillon Reyna
9,531 Points

Where am I going wrong with this?

I don't think I'm understanding what I'm supposed to do with this new route - nor exactly what the question is asking for. What am I missing here?

flask_app.py 
from flask import Flask
from flask import request

app = Flask(__name__)

@app.route('/')
@app.route('/<name>')
def index(name = 'Dillon'):
    name = request.args.get('name', name)
    return 'Hello {name}'.format(name)

1 Answer

Jeremiah Bushau
Jeremiah Bushau
24,061 Points
Jeremiah Bushau
Jeremiah Bushau
24,061 Points

Hi, I made some comments in your code to help out, you're super close.

from flask import Flask
from flask import request

app = Flask(__name__)

@app.route('/')
# We are looking for a keyword arg from a query string 
# so you do not need to create this route :)
# @app.route('/<name>')
def index(name='Dillon'):
    name = request.args.get('name', name)
    # also don't forget to reference your key if using one in your formatting
    # return 'Hello {}'.format(name)  <-- this would work also but would be less explicit
    return 'Hello {name}'.format(name=name)

Hope this helps :)