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Start your free trialVincent Zamora
3,872 Pointsdef timestamp_oldest(*args): ts = list(args) ts.sort(reverse=True) return datetime.datetim
Why doesn't this work?
import datetime
def timestamp_oldest(*args): ts = list(args) ts.sort(reverse=True) return datetime.datetime.fromtimestamp(ts[0].strftime('%Y-%m-%d %H:%M:%S'))
# If you need help, look up datetime.datetime.fromtimestamp()
# Also, remember that you *will not* know how many timestamps
# are coming in.
import datetime
def timestamp_oldest(*args):
ts = list(args)
ts.sort(reverse=True)
return datetime.datetime.fromtimestamp(ts[0].strftime('%Y-%m-%d %H:%M:%S'))
2 Answers
Chris Freeman
Treehouse Moderator 68,423 PointsHey Vincent Zamora, you are VERY clsoe. Two items to correct:
- Since the "oldest" POSIX is the lowest, sorting will naturally put the oldest first. remove
reverse=True
- The method
datetime.datetime.fromtimestamp
takes a POSIX format float by default. remove use ofstrptime
method (which does not exist on afloat
)
Post back if you need more help! Good luck!!
boi
14,241 PointsYou're totally off track here, Vincent. I could give you some direction, do this;
1) Since the number of arguments is not known, create a list
and append all the arguments that will come in.
2) The challenge wants you to return
the oldest POSIX date, meaning the date closest to 1970, 01, 01
, so if the
sort()
method is used on a list
, the sort()
method will sort the values in the list from smallest to
greatest, so the smallest or oldest value will be the first value in the list
.
3) Return the smallest value in the list by using datetime.datetime.fromtimestamp()
method.
If you need help, msg me here.