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Daniel McFarlin
5,168 PointsI'm having troubles understanding the questions here. Haven't used the % much so I am not quite sure
Hey everyone! Don't mean to ask so many questions, but I keep finding myself stumped on some of these code challenges. Anyways I haven't really used the "%" much and so I am not sure how to apply it to this question. I know it deals with division with a remainder, but I don't understand how to use it specifically in this coding problem. Any help y'all can provide would be much appreciated! Thank you! :)
def even_odd(number):
if number is % 2:
return True
else:
return False
3 Answers
doesitmatter
12,885 PointsYou use is to compare if something is None, so don't use it here.
A number is even when it's remainder after devision with 2 equals to 0. This translates to: if num%2==0 then return true else false
Alexander Davison
65,469 PointsYou can use x % 2 == 0 to determine if x is odd. Keep in mind that % is basically calculating the remainder of x divided by 2!
Also, the challenge didn't ask you to edit this function.
Amy Shah
25,337 PointsThe result of % 2 should be zero if even and one if odd. You should include that in a conditional if then statement.
If zero results from %2 then it is even. Etc