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# messy_list = [5,2,1,3,4,7,8,0,9,-1] silly_list = messy_list[12:0:-3]

messy_list = [5,2,1,3,4,7,8,0,9,-1] so create a variable named silly_list that is suppossed to create the same list in reverse and take every three out of that list

silly_list = messy_list[12 :0:-3] returns [-1, 8, 3]

why isn't this right in the console

Classic case on how to overthink the problem (happens to me all the time) :) But it brings up an important lesson on Python slicing and indexing.

## First the solution:

As you probably know, you can copy an entire list by doing this:

list_2 = list_1[:]

We didn't have to specify the start and stop indexes since we want the whole list. Same thing is true in reverse:

silly_list = messy_list[::-3]
print silly_list
[-1, 8, 3, 5]

We could be done there since you now have the solution, but let me explain some of what is happening automatically there. In the above case [::-3], think of it like this:

[a : b : -3]

a is by default -1

b is by default -(len+1)

Thus the statement could be explicitly stated as follows:

silly_list = messy_list[-1:-11:-3]
print silly_list
[-1, 8, 3, 5]

I'm sure they set this assignment up this way intentionally to help people understand how Python slicing works. Hope this helps!