Python Collections: Challenge Task 4 of 5 - Bummer: Couldn't find `most_courses`

Question

Here is the challenge question:
"Wow, I just can't stump you! OK, two more to go. I think this one's my favorite, though.
Create a function named mostcourses that takes our good ol' teacher dictionary.
mostcourses should return the name of the teacher with the most courses. You might need to hold onto some sort of max count variable."
The dictionary will look something like:
{'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
'Kenneth Love': ['Python Basics', 'Python Collections']}
Each key will be a Teacher and the value will be a list of courses.
Your code goes below here.
def mostcourses(courses):
    maxcount =0
    maxteachername =""
    for item in courses:
        teachername=(item)
        i = coureses[item]
        if isinstance(i,str):
            a=1
            if a>maxcount:
                maxcount = a
                maxteachername = teachername
        else:
            a = len(i)
            if a>maxcount:
                maxcount = a
                maxteachername = teachername
    return(max_teachername)
The error I receive seems quite basic that I have not correctly defined the function "most_courses" - obviously I am missing something basic. Anyone have any ideas?

Steven Parker · Accepted Answer

Python is really hard to debug when not formatted!   Use Markdown for code formatting (here's a video about it (https://teamtreehouse.com/library/code)).  And be sure to include your complete challenge code so we can get to the task that has the issue.

Steven Hender · Answer

Thanks, I will use this next time!
for some reason my code now works - thankyou :)

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Steven Hender

Steven Hender

Python Collections: Challenge Task 4 of 5 - Bummer: Couldn't find `most_courses`

The dictionary will look something like:

{'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],

'Kenneth Love': ['Python Basics', 'Python Collections']}

Each key will be a Teacher and the value will be a list of courses.

Your code goes below here.

2 Answers

Steven Parker

Steven Parker

Steven Hender

Steven Hender

Steven Parker

Steven Parker