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Sahil Kapoor
8,932 Points" .remove()" funtion not correctly working inside a loop
PRINT EVEN INDEX NUMBERS ''' python list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] for num in list : if list.index(num) %2 != 0: list.remove(num)
print(list) ''' Wanted output [1, 3, 5, 7, 9,]
Getting output [1, 3, 4, 6, 7, 9, 10]
".remove()" is not removing the odd index numbers as it is supposed to do in the code tell me if there is some error in the code or not ?
2 Answers
Steven Parker
229,744 PointsThe remove function is not the issue.
But when you iterate on something in a loop, and alter that thing while inside the loop, it can have side-effects such as causing elements to be skipped over.
To avoid this, you could iterate on a copy of the thing, or use a different strategy to accomplish the goal.
Sahil Kapoor
8,932 PointsIt worked thanks alot for the help Steven
Sahil Kapoor
8,932 PointsSahil Kapoor
8,932 PointsCan you please tell me the best way to print the desired output as I am getting the same problem quite offen
Sahil Kapoor
8,932 PointsSahil Kapoor
8,932 PointsThanks steven to copy and then use the iterable worked thank you so much
Steven Parker
229,744 PointsSteven Parker
229,744 PointsAnother way would be to generate the items you want instead of removing ones you don't want, and then replace the list with that:
list = [list[i] for i in range(len(list)) if not i % 2]An advantage of this approach is that it would work even if the list contents had repeated values.