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Simphiwe Masukume
7,030 Points'time_string' is an invalid keyword argument for this function'
'time_string' is an invalid keyword argument for this function. Not sure why we need key word arguments in this case and how to implement them
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)
def time_machine(time_int, time_string):
if time_string == "years":
time_int *= 365
time_string = "days"
return starter + datetime.timedelta(time_string=time_int)
2 Answers
Steven Parker
229,732 PointsAs the hint says, "time_string" is not a valid argument name. Valid arguments have names like "minute", "hour", "week", etc. For more details, see the Python documentation page for timedelta.
If you want to create a kwarg using a variable for the argument name, you could pack it into a dictionary and then apply the unpacking operator ("**") on the dictionary.
Pratham Mishra
14,191 Points'''def time_machine(time_int, years): if years == 'years': time_int = 365 years = 'days' return starter + datetime.timedelta(*{years : time_int}) '''