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Python Technical Interview Prep: Python Basics Basic Python Splitsville

Posted by Sergio Andrés Herrera Velásquez
Sergio Andrés Herrera Velásquez
Courses Plus Student 23,765 Points

Uh oh, I didn't get the correct value returned. It should have been '55555' for the zip. Instead, it was ' 55555'

what am I missing here? Bummer: Uh oh, I didn't get the correct value returned. It should have been '

split.py 
# enter your code here
def splitsville(address):
    split_address=address.split(',')
    street,city,state,zip_code=split_address
    dictionary={'street':street,
    'city':city,
    'state':state,
    'zip_code':zip_code,}
    return dictionary

3 Answers

Steven Parker
Steven Parker
229,785 Points
Steven Parker
Steven Parker
229,785 Points

If you look carefully, you'll notice that the "wrong" answer shown in the message has a space in it, but it is expecting the correct value to be just the digits.

So to properly separate your values, the split token needs to be defined as a comma and a space.

Sergio Andrés Herrera Velásquez
Sergio Andrés Herrera Velásquez
Courses Plus Student 23,765 Points

Steven Parker Thank you, it indeed helped me pass the challenge, somehow I missed it, hahaha I really appreciate it

Andy Hughes
Andy Hughes
8,478 Points
Andy Hughes
Andy Hughes
8,478 Points

Hey Sergio,

So your split needs to allow for space around the comma. You'll see that there is a space after each one so include that.

Your function won't be able to understand:

street,city,state,zip_code=split_address

as essentially, you're just creating a new variable. Also, your dictionary syntax is not quite right and you're being asked to 'return' the dictionary not put it inside of a variable.

So your split ( taking account of my comments above ), should produce a list of elements from an address. You could then create a variable that contains your keys i.e.

keys = 'street', 'city', 'state', 'zip_code',

Now you have a split address and your keys separately so they need to be joined. To do this, return your dictionary using the zip function to join 'keys' to 'split_address'. The zip() function produces a list, so you then just need to convert that into a dictionary as follows:

return dict(zip(keys, split_address))

Hope that made sense and helps :)

Sergio Andrés Herrera Velásquez
Sergio Andrés Herrera Velásquez
Courses Plus Student 23,765 Points

Hi,Andy Hughes.

Thank you for your reply, while your answer was very complete, I feel like it was overcomplicating the process and the answer, as to the street,city,state,zip_code=split_address ` part, it was just meant to unpack the values from the split, and then using the variables as values, rather than fixed values. I believe in code being explicit rather than implicit( having to guess or look at more complex options like zip or dict which would need more digging into if anyone would look at the code for the 1st time)

Thank you again

Andy Hughes
Andy Hughes
8,478 Points
Andy Hughes
Andy Hughes
8,478 Points

Actually looking at this again, I realise I had changed your code before realising the space after the comma. If you just change that, the code technically works.

I guess i was trying to use less code and play with concepts shown from other videos. But i totally take your point; if someone doesn't know zip(), it's confusing.

Glad you got it sorted. Happy coding. :)