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# 00000111

what is the answer of 00000111

You could break the number like this:

```binary: 00000111
--------
1 X 1 = 1
2 X 1 = 2
4 X 1 = 4
8 X 0 = 0
16 X 0 = 0
32 X 0 = 0
64 X 0 = 0
128 X 0 = 0
--------
Total of all the digits' values:
decimal: 7
```

starting from the right in binary, each digit's value when it is on or a 1 (same thing) is doubled as you go through the numbers. It's value is always 0 if it is off or 0

For example, if we changed the original number from 00000111 to 10000111 (changed the 8th digit from the right from 0 to 1) we would be adding 128 to the number, since that digit is worth 128 when "on"(1) and 0 when "off"(0)

```binary: 10000111
--------
1 X 1 = 1
2 X 1 = 2
4 X 1 = 4
8 X 0 = 0
16 X 0 = 0
32 X 0 = 0
64 X 0 = 0
128 X 1 = 128
--------
Total of all the digits' values:
decimal: 135
```

Hope this helps.

Thanks Simon for pointing out error