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Java Java Objects Harnessing the Power of Objects Constants

Andrew Husted
Andrew Husted
11,271 Points

2 errors: final variable assignment and String declared when no argument required

I received the following two error messages:

1.) Example.java:6: error: constructor PezDispenser in class PezDispenser cannot be applied to given types;
PezDispenser dispenser = new PezDispenser("yoda");
required: no arguments
found: String
reason: actual and formal argument lists differ in length

2.) ./PezDispenser.java:6: error: cannot assign a value to final variable characterName
this.characterName = characterName;

1- I declare the variable characterName but do not initialize it until within the PezDispenser field, isn't this permitted?

2- I state PezeDispenser takes a String value called characterName within the parentheses, but the error says no argument is required?

Example.java public class Example {

public static void main(String[] args) { // Your amazing code goes here... System.out.println("We are making a new pez despenser"); PezDispenser dispenser = new PezDispenser("yoda"); System.out.printf("The dispenser is %s %n", dispenser.getCharacterName()); }}

PezDispenser.java class PezDispenser{ final private String characterName;

public String PezDispenser(String characterName){ this.characterName = characterName; }

public String getCharacterName(){ return characterName; } }

1 Answer

Chris Jones
.a{fill-rule:evenodd;}techdegree seal-36
Chris Jones
Java Web Development Techdegree Graduate 23,933 Points

Hey Andrew,

You don't have a constructor for PezDispenser. You have:

public String PezDispenser(String characterName){ this.characterName = characterName; }

But, this method is returning a String, not a PezDispenser. You just need to remove the String return type to make this method a constructor:

public PezDispenser(String characterName){ this.characterName = characterName; }

Let me know if you get any more errors after making this change!