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Start your free trial###### James Thomas

6,452 Points# 8*7+8%5+6/2 to me this == 59.6. Apparently I am wrong.

Apparently I am wrong. Please explain?

## 5 Answers

###### Steven Parker

227,140 Points## You're forgetting about operator precedence.

All *multiplicative* operations (which include multiplication, division, and modulus) are performed before any *additive* opertions ( + or - ).

I'll bet you can figure it out now without a spoiler.

###### Dane Parchment

Treehouse Moderator 11,074 PointsOk so for Computer Science the Order of Operations is:

- P ---> Parentheses
- E ---> Exponents
- M ---> Multiplication
- D ---> Division (This is for programming only, division holds the same weight as multiplication
- M ---> Modulos (This is for programming only, and it can has the same order weight as division and multiplication)
- A ---> Addition
- S ---> Subtraction

So by following these rules we know that our addition will be done last and our multiplication, division, and Modulos will be done first, so this could have effectively been written as `(8*7) + (8%5) + (6/2)`

We know that `8 * 7 = 56`

We know that `8 % 5 = 3`

We know that `6 / 2 = 3`

So when we add them all together we get `56 + 3 + 3 ----- or ----- 56 + 6 = 62`

###### Steven Parker

227,140 PointsThere's no common rule for all of "computer science", operator precedence varies with language. For example, in C#, multiplication does __not__ take precedence over division — so **12/2*3** is __18__, not 2.

See the reference page I linked in the title of my answer for more information.

###### Dane Parchment

Treehouse Moderator 11,074 PointsThat is because of associativity, so you are correct there! I realized that I have not specified that division and modulos hold the same weight as multiplication so I will fix that.

###### Steven Parker

227,140 PointsBy the C# rules, the associativity of multiplicative operations is left-to right. That's why 12/2*3 evaluates to 18, instead of 2.

I recommend following the rules of the language you are programming in. If there are "general rules" that the language is "breaking", it doesn't seem like they would be useful to the developer and they could lead to confusion and unexpected program behavior.

###### Dane Parchment

Treehouse Moderator 11,074 PointsI see where you are coming from, I have a math background so I always see that there are general rules (keeps us sane) but in programming I have noticed that some languages seem to break this (for some reason or another).

###### Chris Freeman

Treehouse Moderator 68,404 PointsPEMDMAS does apply in Python where it's more like PE[MDM][AS]

```
>>> 12 / 2 * 3
18.0 # not 2
>>> 12 / 4 % 2 * 3
3.0 # / then % then *
>>> 25 % 13 / 2 * 3
18.0 # % then / then *
>>> 15 - 3 + 2
14 # not 10
```

###### Justin Coberly

16,929 PointsNormally the % (modulo) operator has the same level of precedence as multiplication and division. So in this statement we can evaluate it from left to right.

8*7 = 56 8%5 = 3 <- the remainder is the answer to a modulus expression 6/2 = 3 so... 56+3+3 = 62

###### James Thomas

6,452 PointsExcellent answers, thanks all. Sometimes learning the write software it's difficult to see the wood for the trees but this has been explained well!

###### Umut İnanç

Courses Plus Student 818 PointsI like to put paranteses between numbers which are going to be multiplied, divided or modulated to seperate additive and multiplicative operations to make it easier:

(8*7)+(8%5)+(6/2)

This way you can easily solve it.

(56)+(3)+(3) = 62

## Justin Coberly

16,929 Points## Justin Coberly

16,929 PointsNormally the % (modulo) operator has the same level of precedence as multiplication and division. So in this statement we can evaluate it from left to right.

8*7 = 56 8%5 = 3 <- the remainder is the answer to a modulus expression 6/2 = 3 56+3+3 = 62