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Python Python Collections (2016, retired 2019) Dictionaries Teacher Stats

Posted by Aryan Monga
Aryan Monga
4,061 Points

A quiz question!

Wow, I just can't stump you! OK, two more to go. I think this one's my favorite, though. Create a function named most_courses that takes our good ol' teacher dictionary. most_courses should return the name of the teacher with the most courses. You might need to hold onto some sort of max count variable. What should I write next? With what should I compare the value? Help me please! THANKS! ;)

teachers.py 
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def most_courses(g):
    name=""
    num_courses=0
    for h in e.items():
        name=h.keys()
        num_courses= len(h.values)








def courses(e):
    teachers_list=[]
    for f in e.values():
        teachers_list.extend(f)
    return teachers_list






def num_teachers(a):
    teachers=0
    for b in a:
        teachers = teachers+ 1
    return teachers
def num_courses(c):
    courses=0
    for d in c.values():
        courses = courses + len(d)
    return courses

2 Answers

Steven Parker
Steven Parker
229,744 Points
Steven Parker
Steven Parker
229,744 Points

You already asked this question a few hours ago.

Check that link and the answers already given there by Steve Hunter and Jon Mirow.

Aryan Monga
Aryan Monga
4,061 Points

I know but I didn't understand it completely, could you write something additional for me?

Steven Parker
Steven Parker
229,744 Points
Steven Parker
Steven Parker
229,744 Points

Didn't the answers posted by Steve and Jon help?

Aryan Monga
Aryan Monga
4,061 Points

They did but I couldn't understand much, so I wrote the code as much as I knew! Check it out. Please help me to solve this! ;)

Steven Parker
Steven Parker
229,744 Points
Steven Parker
Steven Parker
229,744 Points

You have a good start but you have a few issues:

  • after the loop, you still need tor return the "name"
  • you can unpack the dictionary in the loop: "for key, values in e.items():"
  • only update the saved name and count when the count is larger than before

See if you can get it now.

Matthew Schwer
seal-mask
.a{fill-rule:evenodd;}techdegree
Matthew Schwer
Python Web Development Techdegree Student 975 Points
Matthew Schwer
.a{fill-rule:evenodd;}techdegree
Matthew Schwer
Python Web Development Techdegree Student 975 Points

def most_courses(treehouse_teachers): highest_num = 0 teacher_most_classes = "" for key, value in treehouse_teachers.items(): if len(value) > highest_num: highest_num = len(value) teacher_most_classes = key return tearcher_most_classes

it says "Bummer: Couldn't find most_courses" so I don't know why it won't even acknowledge the function's existence

Steven Parker
Steven Parker
229,744 Points
Steven Parker
Steven Parker
229,744 Points

If there's an error in the definition, the function will remain undefined. Formatting is crucial to Python, so always use Markdown code formatting when posting code. Also, to reach the community as a whole always start a new question instead of adding one as an "answer" to another question.