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# A Simpler Solution to Which Teachers Don't Have a 1st Period Class

The EXCEPT solution is a good one. Just thought I'd share how I did it:

```SELECT FIRST_NAME, LAST_NAME, MIN(PERIOD_ID) FROM TEACHERS
JOIN CLASSES ON TEACHERS.ID = CLASSES.TEACHER_ID
GROUP BY TEACHERS.ID
HAVING MIN(PERIOD_ID) > 1
```

Another alternative...

```WITH p1_teachers AS (
SELECT period_id, teacher_id FROM classes
WHERE period_id = 1
), list_all AS (
SELECT * FROM teachers LEFT JOIN p1_teachers ON teachers.id = p1_teachers.teacher_id
)

SELECT first_name, last_name FROM list_all WHERE period_id IS NULL;
```

I did the following:

```SELECT * FROM TEACHERS
WHERE TEACHERS.ID NOT IN
(
SELECT TEACHERS.ID FROM TEACHERS
INNER JOIN CLASSES ON CLASSES.TEACHER_ID = TEACHERS.ID
WHERE CLASSES.PERIOD_ID = 1
);
```

My version of the solution:

SELECT * FROM TEACHERS WHERE TEACHERS.ID NOT IN (SELECT TEACHER_ID FROM TEACHERS JOIN CLASSES ON CLASSES.TEACHER_ID = TEACHERS.ID WHERE PERIOD_ID = 1)

A alternate solution with a single subquery and no JOINs:

```SELECT *
FROM TEACHERS
WHERE ID NOT IN
(SELECT TEACHER_ID FROM CLASSES WHERE PERIOD_ID = 1);
```

My solution is similar but easier to read:

```SELECT (first_name || " " || last_name) AS "Available Teacher(s) for Morning Bus Duty" FROM TEACHERS
JOIN CLASSES ON teachers.id = classes.teacher_id
GROUP BY teachers.id HAVING MIN(classes.period_id) > 1;
```

```SELECT T.FIRST_NAME || ' ' || T.LAST_NAME AS FULLNAME, MIN(C.PERIOD_ID) AS FIRST_PERIOD FROM CLASSES AS C
`SELECT * FROM TEACHERS WHERE id NOT IN (SELECT teacher_id FROM CLASSES WHERE period_id = 1)`