Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.
Sylvia Pan7,093 Points
Hey, guys, I've been stuck at this point with the compiler telling me I got '1234567890'. I think I've excluded 5, 6, and 7. Can someone tell me where is the problem?
import re string = '1234567890' good_numbers = re.findall(r'[\d]*[^5-7]',string)
Maxim Andreev24,529 Points
good_numbers = re.findall(r'[^567]', string)
edit: Just to explain, if you have [\d]* in front it will look for any combination of numbers [0-9]* followed by any character except 5,6 or 7.