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PHP

Posted by Tom DuScheid
Tom DuScheid
4,014 Points

Accounting for Empty Results Challenge

Stuck here. Where is the $flavors array that they are talking about?

Let's make sure that foreach loop executes correctly if the $flavors array is NOT empty. Add one element to the $flavors array with a value of 'Avocado Chocolate'.

//My Attempt on this challenge

    $recommendations = array();

?><html> <body>

<h1>Flavor Recommendations</h1>

<?php

            if ($recommendations != "") {
                if (!empty($recommendations)) {
                    echo '<ul class="recommendations">';
                    foreach ($flavors as $flavor) {

                    }
                    echo '</ul>';
                } else {
                    echo '<p>There are no flavor recommendations for you.</p>';
                }
            }

        ?>

</body> </html>

3 Answers

Randy Hoyt
STAFF
Randy Hoyt
Treehouse Guest Teacher
Randy Hoyt
Randy Hoyt
Treehouse Guest Teacher

Two things:

(1) You don't need both of these checks:

if ($recommendations != "") {
    if (!empty($recommendations)) {

The second check alone should be sufficient:

    if (!empty($recommendations)) {

(2) There is supposed to be code inside the foreach loop that displays the flavor. Did you remove that?

foreach ($flavors as $flavor) {

}

Does that help?

Kari Jones
Kari Jones
6,217 Points

Hi, I am also having trouble with this code challenge. It shows a white screen with Flavor Recommendations in the preview, and the message is Bummer! The unordered list tags appear even when the array is empty. Place those tags inside a conditional that uses the empty function. Here is my code:

<?php

    $recommendations = array();

?><html>
<body>

<h1>Flavor Recommendations</h1>

<?php
     echo '<ul>';
     if (!empty($recommendations)) {
        echo '<ul>';
        foreach($recommendations as $flavor) { ?>
            <li><?php echo $flavor; ?></li>
        <?php }
        echo '</ul>';
        } ?>
</body>
</html>

Can anyone help?

Dominik Seliner
Dominik Seliner
511 Points

Hi Kari

You create two ul tags which is one too many Delete the echo '<ul>'; line above the if clause.

kljnnkl gvhhgv
kljnnkl gvhhgv
3,175 Points
kljnnkl gvhhgv
kljnnkl gvhhgv
3,175 Points

What stage is that challenge in?

Saad Khan Malik
Saad Khan Malik
25,199 Points

stage 5

Saad Khan Malik
Saad Khan Malik
25,199 Points
Saad Khan Malik
Saad Khan Malik
25,199 Points

this should help....

<?php foreach($recommendations as $flavor) { ?>
                    <?php if (!empty($recommendations)) {?>
                            <?php echo "<ul>" ?>
                        <li><?php echo $flavor; ?></li>
                                <?php echo "</ul>" ?>
      <?php } }; ?>