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###### Malaya Manjula

6,028 Points# Add a new method named ReverseNumbers that has a return type of IEnumerable<int> and uses a LINQ query to return the _nu

Querying with LINQ, Challenge task 2 of 2, Add a new method named ReverseNumbers that has a return type of IEnumerable<int> and uses a LINQ query to return the _numbers variable in reverse order.

Bummer! The first number in the result of your 'ReverseNumbers' method should be '10', since it's the greatest number, since it's the greatest number in the '_numbers' list.

```
using System.Collections.Generic;
using System.Linq;
namespace Treehouse.CodeChallenges
{
public class NumberAnalysis
{
private List<int> _numbers;
public NumberAnalysis()
{
_numbers = new List<int> { 2, 4, 6, 8, 10 };
}
public IEnumerable<int> NumbersGreaterThanFive()
{
return _numbers.Where(n => n > 5);
}
public IEnumerable<int> ReverseNumbers()
{
return _numbers.OrderByDescending(n=>_numbers);
}
}
}
```

## 4 Answers

###### James Churchill

Treehouse TeacherMalaya,

Let's take a closer look at your current solution.

```
public IEnumerable<int> ReverseNumbers()
{
return _numbers.OrderByDescending(n=>_numbers);
}
```

If we look at the documentation for the `Enumerable.OrderByDescending`

method, we'll see that it requires a parameter named `keySelector`

.

https://msdn.microsoft.com/en-us/library/bb534855(v=vs.110).aspx

The `keySelector`

parameter is "A function to extract a key from an element". When we're working with a collection of objects, we would pass a lambda to return the object property to sort on, like this.

```
OrderByDescending(x => x.Name) // assuming that the object "x" has a "Name" property
```

In this example though, we're working with a collection of integers. So what would we return from our lambda?

In your current solution, you're returning the field `_numbers`

, which is the collection that we're trying to sort. That's definitely not what the LINQ operator is expecting for a return value.

As it turns out, we just need to return each integer value that we're passed, like this.

```
OrderByDescending(n => n)
```

Looks a little weird, huh? Usually, when working with LINQ, you'll be working with a collection of objects, so you won't see these kinds of expressions very often.

I hope this helps.

Thanks ~James

###### Mohammed Hossen

5,591 Points# Method 1:

```
public IEnumerable<int> ReverseNumbers()
{
return _numbers.OrderByDescending(n => n >= 10);
}
```

# Method 2:

```
public IEnumerable<int> ReverseNumbers()
{
return _numbers.OrderByDescending(n => n >= _numbers.Max());
}
```

###### Carel Du Plessis

Courses Plus Student 16,356 Pointshow would the Challenge task 2 of 2 code look like if we had to use OrderByDescending on the code below.

```
public IEnumerable<int> NumbersGreaterThanFive()
{
return _numbers.Where(n => n > 5);
}
```

I have tried to do it my self but I only receive compile errors

###### James Churchill

Treehouse TeacherCarel,

Could you please share your code?

Thanks ~James

###### Carel Du Plessis

Courses Plus Student 16,356 Pointsthe commented out code is me trying to use ThenByDescending key word to change the out put in a Descending order

after many failed attempts with OrderByDescending for example

_numbers.OrderByDescending(_numbers.Where(n => n > 5));

but i found a solution to replace them _numbers.Where(n => n > 5).Reverse();

```
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace LINQCodeChallenges
{
class Program
{
static void Main(string[] args)
{
NumberAnalysis mc = new NumberAnalysis();
IEnumerable<int> num1 = mc.NumbersGreaterThanFive();
Console.WriteLine("NumbersGreaterThanFive()");
foreach (int n in num1)
{
Console.WriteLine(n);
}
Console.WriteLine();
IEnumerable<int> num2 = mc.ReverseNumbersGreaterThanFive();
Console.WriteLine("Reverse Numbers Greater Than Five");
foreach (int n in num2) {
Console.WriteLine(n);
}
Console.ReadKey();
}
}
public class NumberAnalysis
{
private List<int> _numbers;
public NumberAnalysis()
{
_numbers = new List<int> { 2, 4, 6, 8, 10 };
}
public IEnumerable<int> NumbersGreaterThanFive()
{
return _numbers.Where(n => n > 5);
}
public IEnumerable<int> ReverseNumbersGreaterThanFive()
{
//return _numbers.OrderBy(n => n > 5).ThenByDescending(n => n);
return _numbers.Where(n => n > 5).Reverse();
}
}
}
```