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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.  # Add a static method named CalculateHypotenuse to the RightTriangle class

I've tried two different ways of calculating the hypotenuse and both ways, I get the error: "Bummer! Is your math correct?"

Am I calculating it wrong?

RightTriangle.cs
```namespace Treehouse.CodeChallenges
{
class RightTriangle
{
public static double CalculateHypotenuse (double side1, double side2)
{
return System.Math.Pow(side1, 2) + System.Math.Pow(side2, 2);
//return (side1 * side1) + (side2 * side2);
}
}
}
``` STAFF

Your code is great! Your math is a little off. Let's take a triangle with the sides 3, 4, 5. The formula is a^2 + b^2 = c^2. So 9 + 16 = 25. So if we want to solve for the hypotenuse we take the squares of both sides and add them, which you did perfectly. But then we take the square root of the result.

```namespace Treehouse.CodeChallenges
{
class RightTriangle
{
public static double CalculateHypotenuse (double side1, double side2)
{
return System.Math.Sqrt(System.Math.Pow(side1, 2) + System.Math.Pow(side2, 2));
//return (side1 * side1) + (side2 * side2);
}
}
}
```

You are just missing one tiny math function. Hope this helps!  Can somebody help me with my code? I read the answer already, but I didn't just want to copy-paste. Would my code ever work as it's been written (with some kind of get modification?) Thanks!

```namespace Treehouse.CodeChallenges
{
class RightTriangle
{
private static double CalculateHypotenuse
{
double a = x;
Console.WriteLine("Insert the length of a:"); Yes, and no. First you would have to redo how you're getting and assigning the input from the user. But furthermore, it would only work if the user put in 2 for both sides. The reason being is that you have x to the power of x. This means if they enter 2 for x it would be 2 the the power of 2 (which is valid for the Pythagorean theorem). However, if the user put in 5 for x it would be 5 to the power of 5 when what you want is 5 to the power of 2. This would result in you having a value of 3125 where you should really only have a value of 25. That's a large difference. hope this helps! 