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Add a try block before where you turn your arguments into floats. Then add an except to catch the possible ValueError.
Hi I tried to solved this but I always get an error
This is the code
def add(num1, num2): try: float(num1)+float(num2) except ValueError: return None else: return float(num1)+float(num2)
How come this is wrong?
Nathan Tallack22,159 Points
When you are pasting your code into the forum, try using the markdown so that the code formats correctly. That way we can see if there are any indentation problems with your code. Click the Markdown Cheatsheet below your input box for info on how this is done.
Consider how my code result for this challenge is formatted when displayed using correct Markdown.
def add(num1, num2):
result = float(num1) + float(num2)
My code differs from yours in that I have moved the return outside of the try statement. So in my code I am assigning float(num1) + float(num2) result to a variable named result. Then if that works I am returning that result value. If it does not work in the try block then the ValueError will trigger an early return of None and the return result will not be executed by the function.
I think they call this "early return" or some such thing. :)
Hello! I've tried your code and it worked. Probably you have to indent smth. Good luck!
Thomas Souza7,943 Points
def add(a, b): try: x = float(a) y= float(b) count = x + y except ValueError: return None else: return (count)