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Java Java Basics Perfecting the Prototype String Equality

Marcus Rajala
Marcus Rajala
444 Points

Add an if Statement comparing two strings.

I keep getting a compiler error and I don't quite know what I'm doing wrong!

String firstExample = "hello"; String secondExample = "hello"; String thirdExample = "HELLO"; if (firstExample.equalsIgnoreCase(secondExample)); { console.printf("first is equal to second \n."); System.exit(0); }

Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equalsIgnoreCase(secondExample)); {
  console.printf("first is equal to second \n.");
    System.exit(0);
}

3 Answers

Allan Clark
Allan Clark
10,810 Points

Just delete the System.Exit, its not needed in the Treehouse Challenges

Kimsreng Lim
Kimsreng Lim
1,226 Points

In your if statement, remember there is no semicolon(;) after the parenthesis.

Marcus Rajala
Marcus Rajala
444 Points

Thanks for your help gents!