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vinicius reis
439 PointsAdd another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out...
i dont know why it's wrong
// I have imported a java.io.Console for you, it is named console.
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equals(secondExample));
console.printf("first is equal to second");
if (firstExample.equalsIgnoriCase(thirdExample));
console.printf("first and third are the same ignoring case");
1 Answer

Rumyana Dimitrieva
Java Web Development Techdegree Graduate 18,632 PointsHi Vinicius, There are some problems with your code - the syntax of the if statement is:
if(condition){
//code to be executed
}
there should not be a semicolon (;) after the condition, and you are missing the curly braces{}
if (firstExample.equals(secondExample)){
console.printf("first is equal to second");
}
I am sure you can fix the second if statement.
There is also a typo in the equalsIgnoriCase method - it should be equalsIgnoreCase
I hope it helps. Good luck!