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Java Java Basics Perfecting the Prototype String Equality

Posted by vinicius reis
vinicius reis
439 Points

Add another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out...

i dont know why it's wrong

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equals(secondExample));
    console.printf("first is equal to second");
if (firstExample.equalsIgnoriCase(thirdExample));
console.printf("first and third are the same ignoring case");

1 Answer

Rumyana Dimitrieva
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Rumyana Dimitrieva
Java Web Development Techdegree Graduate 18,632 Points
Rumyana Dimitrieva
.a{fill-rule:evenodd;}techdegree seal-36
Rumyana Dimitrieva
Java Web Development Techdegree Graduate 18,632 Points

Hi Vinicius, There are some problems with your code - the syntax of the if statement is: 

if(condition){  
//code to be executed  
}

there should not be a semicolon (;) after the condition, and you are missing the curly braces{}

  if (firstExample.equals(secondExample)){
    console.printf("first is equal to second");
}

I am sure you can fix the second if statement.

There is also a typo in the equalsIgnoriCase method - it should be equalsIgnoreCase

I hope it helps. Good luck!