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Java Java Basics Perfecting the Prototype String Equality

Add another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out "fi

Add another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out "first and third are the same ignoring case".

I typed: if (firstExample.equalsIgnoreCase() == thirdExample) { console.printf("first and third are the same ignoring case.");+ }

and error message said it doesn't recognize the equals method....

Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if (firstExample == secondExample) {
    console.printf("first is equal to second");
}

if (firstExample,equalsIgnoreCase() == thirdExample{
    console.printf("first and third are the same ignoring case");
}

2 Answers

Rob Bridges
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.a{fill-rule:evenodd;}techdegree seal-36
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,459 Points

Hey there Luke,

Looks like the only trouble that you are having is with calling the .equals and .equalsIgnoreCase, you are super close, you just need to pass in the argument that you want them to compare to.

generally it's best to not use == when comparing strings, as the .equals() method works better.

I showed some code below that should help, let me know if it doesn't.

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if (firstExample.equals(secondExample)) {
  console.printf("First and second are equal");
}
if (firstExample.equalsIgnoreCase(thirdExample)) {
  console.printf("first and third are the same ignoring case");
}
juan lourido
juan lourido
460 Points

thank you very much

It worked! thank you!