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Java Java Basics Perfecting the Prototype String Equality

Add another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out "fi

Putting this down, the exact way everyone else has. And I'm still getting errors. Please help!

Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if(firstExample.equalsIgnoreCase(thirdExample)){
 console.printf("first and third are the same ignoring case");
}

5 Answers

Are you able to run this code locally (on your own machine) or a workspace? Maybe you can debug that way.

I used

if(firstExample.equalsIgnoreCase(thirdExample)){
 console.printf("first and third are the same ignoring case");
}

as you wrote it here and it work just fine. Maybe reset the code and try again.

In first place you are using console.printf.to output something in java we make use of System.out.print();

Its important when you are writing an if statement to also provide the else to handle fallbacks if you condition is not met.Note Console.write is used in c#

Also note u are using console.prinf in java to format string but you didn't provide the string to format

Try system.out.printf("%s",string at);