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PHP

Posted by Adam Menczykowski
Adam Menczykowski
2,319 Points

Add subdomain to current domain

Hi guys,

I have created a welsh version of an originally English website.

English: xperiorfarmhealth.co.uk Welsh: welsh.xperiorfarmhealth.co.uk

What I want to do is link on every page in the header to the corresponding welsh version.

I have managed to parse the current url ( http://xperiorfarmhealth.co.uk/vets/ ) into a string....

$current_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$link_array = parse_url($current_link);
var_dump ($link_array);

Which outputs:

array(3) { ["scheme"]=> string(4) "http" ["host"]=> string(12) "xperiorfarmhealth.co.uk" ["path"]=> string(6) "/vets/" }

How can I add "welsh" after the scheme and before the host, then turn it back into a url? I want the result to be: http://welsh.xperiorfarmhealth.co.uk/vets/

Also I want to do the exact reverse of that, turning http://welsh.xperiorfarmhealth.co.uk/vets/ into http://xperiorfarmhealth.co.uk/vets/

Thanks in advance guys Adam

Noah Laurent
Noah Laurent
3,080 Points

Hello Adam, did you use WordPress? WordPress Multisite? Thanks, Laurent

6 Answers

Michael Collins
Michael Collins
433 Points

$current_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]"; $link_array = parse_url($current_link);

we need to prepend "welsh" into the $link_array['host'];

$link_array['host'] = 'welsh.' . $link_array['host'];

here we concatenate the various parts to make the new URL link

$new_link = $link_array['scheme'] . '://' . $link_array['host'] . $link_array['path'];

Adam Menczykowski
Adam Menczykowski
2,319 Points
Adam Menczykowski
Adam Menczykowski
2,319 Points

Awesome, I'll try it out. Thanks so much

Adam Menczykowski
Adam Menczykowski
2,319 Points
Adam Menczykowski
Adam Menczykowski
2,319 Points

Also, how can I do the reverse of that process, removing welsh, so that I can link to the corresponding english page?

Adam Menczykowski
Adam Menczykowski
2,319 Points
Adam Menczykowski
Adam Menczykowski
2,319 Points

Also, how can I do the reverse of that process, removing welsh, so that I can link to the corresponding english page?

Michael Collins
Michael Collins
433 Points
Michael Collins
Michael Collins
433 Points

So assuming that $link_array['host'] is already populated with with a value beginning with "welsh."

$link_array['host'] = preg_replace('/^welsh\./', '', $link_array['host']);

The carrot (^) means that the pattern "welsh." must be found at the beginning to match. The (.) means that the period should be treated as literal period. Without the backslash, the period is a meta character which means ANY character.

preg_replace takes $link_array['host'] as the subject. It then looks for the pattern (welsh.) only at the beginning. If it finds the pattern, it replaces it with nothing ('').

Adam Menczykowski
Adam Menczykowski
2,319 Points
Adam Menczykowski
Adam Menczykowski
2,319 Points

Thank you so much, and thank you for the extra explanation in addition to the solution.