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Start your free trialNicholas Arcuri
11,311 Points"Add the code to open the AJAX request using the GET method and pointing to the 'footer.html' file." Answer not working
Unless I'm missing something, it's not accepting my answer:
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
request.open('GET', 'footer.html');
};
4 Answers
Dave McFarland
Treehouse TeacherYou have the request.open('GET', 'footer.html');
inside the onreadystatechange
callback. It has to be outside of that (after the last closing brace.)
The onreadystatechange
callback only ever runs AFTER the .open()
and .send()
methods are executed.
Franklin De Los Santos
2,706 Pointsmore specific:
request.open('GET', 'footer.html', true);
UPDATE:
ok try to add status to if statement and in request.open use double quotes and add the two last lines after open like below:
if (request.readyState === 4 && request.status === 200) {
document.getElementById("footer").innerHTML = request.responseText;
}
request.open("GET", "footer.html", true);
request.onreadystatechange = handleServerResponse;
request.send();
Agapito Cruz
21,486 PointsHi Nicholas,
Not sure, but I think you may need to add a third argument in your call to open() for the async value: true for asynchronous, false for synchronous.
-Agapito
Nicholas Arcuri
11,311 PointsNah that's not doing it. A bug maybe?
Nicholas Arcuri
11,311 PointsNicholas Arcuri
11,311 PointsOh wow, I had a feeling I was doing something dumb. Thanks Dave!