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Aaron Gates1,573 Points
Adding to int
I added the following code $integerOne = 1; $integerTwo = 2; var_dump( $integerOne + 5); var_dump( $integerTwo - 1);
but am told that I have not changed $integerOne. It works in the compiler. Not sure what I am doing wrong.
<?php //Place your code below this comment $integerOne = 1; $integerTwo = 2; var_dump( $integerOne + 5); var_dump( $integerTwo - 1); ?>
Amy Kelly3,588 Points
I think it may be because you are doing it as a var_dump which means that the new value is not getting saved, which is why it is saying that you have not changed $integerOne. My solution to this is to change the actual variables:
$integerOne = 1; $integerTwo = 2; $integerOne += 5; $integerTwo -= 1;