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PHP PHP Basics Unit Converter Manipulating Numbers

Aaron Gates
Aaron Gates
1,573 Points
Posted by Aaron Gates
Aaron Gates
1,573 Points

Adding to int

I added the following code $integerOne = 1; $integerTwo = 2; var_dump( $integerOne + 5); var_dump( $integerTwo - 1);

but am told that I have not changed $integerOne. It works in the compiler. Not sure what I am doing wrong.

index.php 
<?php

//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
var_dump( $integerOne + 5);
var_dump( $integerTwo - 1);
?>

1 Answer

Amy Kelly
Amy Kelly
3,588 Points
Amy Kelly
Amy Kelly
3,588 Points

I think it may be because you are doing it as a var_dump which means that the new value is not getting saved, which is why it is saying that you have not changed $integerOne. My solution to this is to change the actual variables: 

$integerOne = 1;
$integerTwo = 2;
$integerOne += 5;
$integerTwo -= 1;
Aaron Gates
Aaron Gates
1,573 Points
Aaron Gates
Aaron Gates
1,573 Points

Thanks Amy, that worked.