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Start your free trialMovrard Herard
Courses Plus Student 543 Pointsadding two items instead of one in program
whenever i add an item to the list it is added twice. I cant understand why.
import os
shopping_list = []
def clear_screen(): os.system("cls" if os.name == "nt" else "clear")
def show_help(): clear_screen() print("What should we pick up at the store?") print(""" Enter 'DONE' to stop adding items. Enter 'HELP' for this help. Enter 'SHOW' to see your current list. """)
def add_to_list(item): show_list() if len(shopping_list): position = input("Where should I add {}?\n" "Press ENTER to add to the end of the list\n" "> ".format(item)) else: position = 0
try:
position = abs(int(position))
except ValueError:
position = None
if position is not None:
shopping_list.insert(position-1, item)
else:
shopping_list.append(new_item)
show_list
shopping_list.append(new_item)
print("Added! List has {} items.".format(len(shopping_list)))
def show_list(): clear_screen() print("Here's your list:")
index = 1
for item in shopping_list:
print("{}. {}".format(index, item))
index += 1
print("-"*10)
show_help()
while True: new_item = input("> ")
if new_item.upper() == 'DONE' or new_item.upper() == "QUIT":
break
elif new_item.upper() == 'HELP':
show_help()
continue
elif new_item.upper() == 'SHOW':
show_list()
continue
else:
add_to_list(new_item)
show_list()
1 Answer
Steven Parker
231,269 PointsIt's hard to read unformatted code, but the issue seems to happen on these lines:
if position is not None:
shopping_list.insert(position-1, item) # this line may add the item the first time
else:
shopping_list.append(new_item) # ...or this one will
show_list
shopping_list.append(new_item) # then this line adds it again
In future questions, use the instructions for code formatting in the Markdown Cheatsheet pop-up below the "Add an Answer" area. Or watch this video on code formatting.