After I did the "except ValueError as err", I can't get the right error message when i enter "blue".

Question

I wrote the "except ValueError as err"-code, and I get the right error message when I enter that I want to buy more tickets than are available. But now, It does not work when I write an invalid input such as "blue", then I get this output: 
What is your name?    Gallahad                                                
How many tickets would you like, Gallahad?   blue                             
Oh no, we ran into an issue. invalid literal for int() with base 10: 'blue'. P
lease try again.                                                              
There are 100 tickets remaining.  
What is your name? 
This is how my code looks like:
python
    try:  
      amount_tickets = int(amount_tickets)
      if amount_tickets > tickets_remaining:
        raise ValueError("There are only {} tickets remaining".format(tickets_remaining))
    except ValueError as err:
      print("Oh no, we ran into an issue. {}. Please try again.".format(err))

Thankful for some help!
/Martina

Chris Freeman · Accepted Answer

Not sure what behavior you are expecting, but it is operating correctly. When a int('blue') is attempted it raises a ValueError and the code immediate moves to the except block. The message is correct invalid literal for int() with base 10: 'blue'. That is, the invalid literal "blue" can not be converted by int().
In the test example below, you can see that the print statement is not executed.
```python
try:
...     int('blue')
...     print("got here")
...     if True:
...         raise ValueError("There are only x tickets left")
... except ValueError as err:
...     print("oh, no", err)
... 
oh, no invalid literal for int() with base 10: 'blue'
```
Post back if you need more help. Good luck!

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Martina Frisk

Martina Frisk

After I did the "except ValueError as err", I can't get the right error message when i enter "blue".

1 Answer

Chris Freeman

Chris Freeman

Martina Frisk

Martina Frisk